Question 222574
how much water should be added to 1 gallon of pure antifreeze to obtain a solution of 95% antifreeze?
.
Let x = gallons of water added
then
1 = .95(1+x)
1 = .95+.95x
.05 = .95x
.05/.95 = x
.0526 gallons = x (amount of water to add)