Question 29896
{{{ 6x-2y=10 }}} and {{{ 3x-5=y }}} since the second equation is already solved for y I will use substitution.  
{{{ 6x-2y=10 }}} plug in the second equation {{{ 3x-5 }}} for y
{{{ 6x-2(3x-5)=10 }}} distribute the 2 watch your signs!!
{{{ 6x-6x+10=10 }}} combine like terms
{{{ 10 = 10 }}} We know this to be a true statement, but does not answer what the point of intersection is, so let's look at the first equation again.
{{{ 6x-2y=10 }}} all numbers are divisable by 2 ... lets divide.
{{{ 6x/2-2y/2=10/2 }}} 
{{{ 3x-5=y }}} But that is the second equation.  So that means that they are in fact the exact same line, and have an infinite number of solutions.