Question 222465
a set of data is normally distrubuted with a mean of 16 and a standard deviation of 0.3.what percent of the data is between 15.2 and 16?
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Find the z-values of 15.2 and of 16.
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z(15.2) = (15.2-16) / 0.3 = -2.6667
z(16) = 0
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P(15.2 < x < 16) = P(-2.667 < z < 0) = 0.1051
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Cheers,
Stan H.