Question 222400
Hint: If you let {{{z=x^2}}}, then {{{z^2=x^4}}}. So you can substitute 'z' for {{{x^2}}} and {{{z^2}}} for {{{x^4}}} to get {{{6z^2-19z+15=0}}}. From there, use the quadratic formula to find 'z'. Once you have solutions in terms of 'z', use the equation {{{z=x^2}}} to find solutions in terms of 'x'.