Question 222227
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Pick any two of the points given.  Let's use (0,3) and (3,3).  Let's calculate the slope of the line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m = \frac{y_1 - y_2}{x_1 - x_2} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m = \frac{3 - 3}{0 - 3}\ =\ 0]


Notice that no matter which pair of points you select, you will have a numerator of zero in the slope fraction, hence the slope is zero.


The line intersects the *[tex \Large y]-axis at (0,3), hence the *[tex \Large y]-intercept is 3.


Now we can use the slope-intercept form of the equation of a line to write the equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 0x\ +\ 3]


or more simply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 3]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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