Question 222131
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I don't know what an interger is.  Furthermore, you didn't say what it is you want to know, but I'm going to go out on a limb and guess that you want to know the value of each of three consecutive integers where three times the smallest is 8 more than the sum of the two larger integers.


Let *[tex \Large x] represent the smallest integer.  Then the next consecutive integer is *[tex \Large x + 1] and the next one is *[tex \Large (x + 1) + 1 = x + 2].


Three times the smallest: *[tex \Large 3x]


The sum of the two larger: *[tex \Large (x + 1) + (x + 2) = 2x + 3]


8 more than that: *[tex \Large 2x + 3 + 8 = 2x + 11]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x = 2x + 11]


Solve for *[tex \Large x] to get the value of the smallest integer, then add one to get the next larger one, and add 2 to get the largest one.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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