Question 222001
<font face="Garamond" size="+2">


Let *[tex \Large w] represent the width of the rectangle.  The length is 3 inches more than that, so if the length is *[tex \Large l] then *[tex \Large l = w + 3] (that's your expression for length in terms of width)


The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P = 2l + 2w].


Let's plug in what we know:


The width is *[tex \Large w], the length is *[tex \Large w + 3], and the perimeter is 30, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(w + 3) + 2w = 30]


That is now an equation to find the width of the triangle.  Just solve for *[tex \Large w] to get the width, and add 3 to get the length.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>