Question 221991
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ E = IR]


So for a constant resistance, you have to double the current in order to double the voltage.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P = EI]


Double current and double voltage is then 4 times the power



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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