Question 221656
Hi, I have an absolute value problem. I tried solving it like a regular equation, but when I check it it is wrong. The problem is 6|5x+45|-113=7.
Thanks in advance.


Step 1.  Note that {{{abs(5x+45)}}} is the same as 5x+45 when 5x+45 is positive and -(5x+45) when 5x+45 is negative.


Step 2.  Let {{{z=abs(5x+45)}}}


{{{6z-113=7}}}


Add 113 to both sides


{{{6z-113+113=7+113}}}


{{{6z=120}}}


Divide 6 to both sides of the equation


{{{6z/6=120/6}}}


{{{z=20}}}


{{{20=5x+45}}} and {{{20=-(5x+45)}}} or {{{-20=5x+45}}}


{{{-25=5x}}}  and {{{-65=5x}}}


{{{x=-5}}}  and {{{x=-13}}}


Step 3.  ANSWER is x=-5 and x=-13.


I hope the above steps were helpful. 


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Respectfully,
Dr J


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