Question 221603
{{{48w^6*x^2*y^4*z/(-6w^2*x^2*y^3)=(-8w^(6-2)*y^(4-3)*z)=(-4w^(4)*y^(1)*z)=(-4w^(2)*y*z)}}}
in case you were wondering what happened to x^2 terms, they canceled out :)