<PRE><B>Question 221598</B>
what is the equation of a line that is perpendicular to the graph of 
3y-4x= -21, and goes through the point (-1,0).How do i write the answer in slope-intercept and standard form?
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Given line: 3y-4x = -21
y = (4/3)x - 7
slope = 4/3
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Perpendicular Line?
slope = -3/4
Find intercept if y = 0 when x = -1.
y = mx + b
0 = (-3/4)(-1) + b
b = -3/4
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Equation: 
y = (-3/4)x - 3/4
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Standard Form:
(3/4)x + y = -3/4
Multiply thru by 4 to get:
3x + 4y = -3
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Cheers,
Stan H.
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{{{graph(400,300,-10,10,-10,10,(-3/4)x-(3/4),(4/3)x - 7)}}}
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