<PRE><B>Question 221521</B>
write a quadratic function in standard form whose graph passes through the given points: 
(1,-2),(-2,1),(3,6)
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Form: ax^2 + bx + c = y
Substitute each point for the x and the y values
to get 3 equations. Then solve the system for a,b,c.
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Using(1,-2) you get: a + b + c = -2
Using(-2,1) you get:4a -2b + c = 1
Using(3,6) you get:9x^2+3b + c = 6
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Solve by any method you know to get:
a = 1
b = 0
c = -3
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Cheers,
Stan H.</PRE>