Question 221447
First we set the equation to 0
x^2 + 45 = 6x subtract 6x from both sides
x^2 - 6x + 45 = 0
Now you must use the quadratic equation to solve
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
where ax^2 + bx + c = 0, and a can not equal 0
*[invoke quadratic "x", 1, -6, 45 ]
Basically when you work out the quadratic equation, you end up with a negative number under the radical which gives you an imaginary number. Unless you have been working with imaginary numbers, this means there is no solution. Graphically, when you solve for x, you are trying to find the x-intercepts. In this case, the graph never crosses the x-axis and there are no x-intercepts.