Question 29555
Let cost of 1 apple = $a
Let cost of 1 orange = $b

Now according to first condition i.e. 4 apples and 2 oranges  equal $1 ..we get the equation.... 

4a + 2b = $1.00.............(1)

Now according to second condition i.e. 2 apples and 3 oranges equal $0.70 ..we get the equation.... 


2a + 3b = $0.70...............(2)..

Now multiply (2) by 2 ,,,we get

4a + 6b = $1 .40..............(3)

By applying elimination method in (1) and (3)....you can get the cost of apples and oranges..

Still if you won't be able to solve further, contact me again. 

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