Question 221296
x/2x-3 - 1/x=2
------------------
{{{x/(2x-3) - 1/x = 2}}}
You have to combine the 2 terms on the left.  Find a common denominator.
A common DEN can always be found by multiplying the DENs.  It might not be the Least CD, but it will give the same answer.
(2x-3)*x = 2x^2 - 3x = DEN
------------
x/(2x-3) = x^2/DEN
1 = (x^2-3x)/DEN
Add those
--> (2x^2 - 3x)/DEN
{{{(2x^2 -2x)/DEN = 2}}}
Multiply thru by DEN
{{{2x^2 - 2x = 2(2x^2 - 3x)}}}
{{{2x^2 - 2x = 4x^2 - 6x}}}
{{{2x^2 - 4x = 0}}}
{{{x^2 - 2x = 0}}}
x(x-2) = 0
x = 0
x = 2