Question 221224
The length of a rectangle is 6 cm more than the width. The area is 11 cm2. Find the length and width.
lets call width w, then length will be w+6 since area is 11 then
w(w+6)=11
w^2+6w-11=0
{{{w = (-6 +- sqrt( 6^2-4*1*(-11) ))/(2*1) }}} 
{{{w = (-6 +- sqrt( 36+44 ))/2 }}} 
{{{w = (-6 +- sqrt( 80 ))/2 }}} 
{{{w = (-3 +- 4*sqrt( 5 )) }}} since our answer can't be negative because width can't be negative our answer would be
{{{w = (-3 + 4*sqrt( 5 )) }}} (about 5.9) and since length was 6 more than width
then length is 
{{{l = (-3 + 4*sqrt( 5 ))+6 = (3 + 4*sqrt( 5 )) }}} (about 11.9)