Question 221204
simplify imaginary i^33 as much as possible


When calculating large powers of {{{i}}}, we simply need to divide the exponent by 4, and the remainder is our answer. That is:


{{{i^33}}} = {{{i^(33/4)}}} = {{{i^8}}} and remainder of {{{i^1}}}. As mentioned before, this remainder {{{i^1}}} will be the answer, which is {{{highlight_green(i)}}}