Question 221143
A rectangle with an area of 112 squares yards has length 6 yards more than its width. Find the perimeter of the rectangle.


Step 1.  Let w be the width.


Step 2.  Let w+6 be the length


Step 3.  Perimeter P means adding up all four sides of the rectangle.


Step 4.  Then P=w+w+w+6+w+6=4w+12.


Step 5.  Area A is the product of the width and length.


Step 6.  Then A=w(w+6)=112.  or {{{w^2+6w-112=0}}}


Step 7.  Use the quadratic formula to solve for positive.  Quadratic formula is given as  {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


where a=1, b=6, and c=-112.


*[invoke quadratic "w", 1, 6, -112 ]


With w=8 , then in Step 4 P=4w+12=4*8+12=44


Step 8.  ANSWER:  The perimeter is 44 yards.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J


drjctu@gmail.com


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