Question 221109
This has been troubling me for some time now: How many gallons of an 8% acid solution and a 22% acid solution need to be mixed to make 14 gallons of a 13% acid solution?
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14 gal of 13% = 1.82 gal of acid
E + T = 14 (8% + 22%)
E*0.08 + T*0.22 = 1.82 (acid in solution)
8E + 22T = 182
E + T = 14 -->T = 14-E
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8E + 22(14-E) = 182
8E + 308 - 22E = 182
-14E = -126
E = 9 gallons
T = 5 gallons
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If they're mixed in equal amounts, the % will be the average, = 15%
Using more 8% will make the result less than 15%, as it does.