Question 221067
< A is three times as large as its supplement, < B
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< A = 3< B
< B = 180-< A
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Substitute for < A and solve for < B
< B = 180-3< B
4< B = 180
< B = 45 Degrees
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Solve for < A
< A = 3(45) = 135 degrees
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< A is one eigth as large as its complement, < B
<  B = 90-<A
< A = 8< B
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Substitute for <A and solve for <B
< B = 90-8< B
9< B = 90
< B = 10 degrees
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< A = 8(10) = 90 degrees
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Cheers,
Stan H.