<PRE><B>Question 220965</B>
HAVING PROBLEMS SOLVING QUADRATIC EQUATIONS INVOLVING FRACTIONS E.G 

4 OVER 2X-3 - 2 OVER X = 1 OVER NINE.


{{{4/(2x-3)-2/x=1/9}}}


Step 1.  To get rid of fractions multiply by 9x(2x-3) to both sides of the equation:


{{{9x(2x-3)*4/(2x-3)-9x(2x-3)*2/x=9x(2x-3)*1/9}}}


{{{36x-18(2x-3)=9x(2x-3)}}}


{{{36x-36x+54=18x^2-27x}}}


Step 2.  Subtract{{{54}}} to both sides of the equation:


{{{54-54=18x^2-27x-54}}}


{{{0=18x^2-27x-54}}}


{{{0=2x^2-3x-6}}}


Step 3.  Solving using the quadratic formula yields


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


where a=2, b=-3, and c=-6


*[invoke quadratic &quot;x&quot;,2, -3, -6 ]


I hope the above steps were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J



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