Question 220635
n = 7
m = 8
range = 1 to 10
high = h
low = l
n = 5
m = 7.8
least possible score to remove
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T1 = 7*8 = 56
T2 =  5*7.8 = 39
R = 56-39 = 17
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H + L = 17
L = 17 - H
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highest score is 10
L = 17 - 10 = 7
lowest score had to be 7
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the average times the number of items equals the total score
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7 * 8 = 56 total score
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5 * 7.8 = 39 total score
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difference between 7 and 5 is 2
difference between 56 and 39 is 17
2 papers had to have a total score of 17
lowest score plus highest score had to add up to 17.
lowest score could not be lower than 7 because that would make the highest score greater than 10 which is not possible.
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