Question 220613
Factor by "grouping":
.
{{{t^3+6t^2-2t-12}}}
{{{(t^3+6t^2)-(2t+12)}}}  Notice, the "sign" change!
{{{t^2(t+6)-2(t+6)}}}
Now, factor out (t+6):
{{{(t+6)(t^2-2)}}}
But, wait, we're not done.  Look at the right term, it can be factored:
{{{(t+6)(t+sqrt(2))(t-sqrt(2))}}}