Question 220533
Remember that {{{x^(y+z)=x^y*x^z}}}. So this means that {{{e^(x+3)=e^x*e^3}}}. If you let {{{z=e^x}}} you can rewrite the equation into {{{e^3z=z+9}}} and easily solve for 'z' (since it's now a linear equation). Once you have the solution in terms of 'z', use the equation {{{z=e^x}}} to find the solution in terms of 'x'.


Note: 'e' is just the constant number 2.71828...