<PRE><B>Question 220545</B>
The sum of three numbers is 105. The second number is 10 larger than the first and the third is one-half the second. Find the three numbers.
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a + b + c = 105
b = a+10
c = (1/2)b
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Rearrange:
a + b + c = 105
a - b + 0 = -10
0 + b -2c =  0
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Use any method you know to find:
a = 36
b = 46
c = 23
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Cheers,
Stan H.</PRE>