Question 220528
Find the solutions of the log. equation 
logx+log(x-19)=log(3x) 
x=?
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log(x(x-19)) = log3x
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x(x-19) = 3x
x^2-19x-3x = 0
x^2-22x = 0
x(x-22) = 0
x = 0 or x = 22
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Cheers,
Stan H.