Question 220517
Solve for x in terms of k 
log{subscript 5}x + log{subscript 5)(x+2) = k 
x= ?
Find x if k=8 ?
------------------------
log5(x) + log5(x+2) = k
Rewrite:
log4[x(x+2)] k
x^2+2x = 4^k
--------------------
Now, if k = 8 you get:
x^2 + 2x = 4^8
---
x^2+2x- 65536 = 0
Comment:
This does not factor neatly.
It can be solved using the quadratic formula.
I'll leave that to you.
Cheers,
Stan H.