Question 220510
Hint: Rewrite {{{e^(2x)}}} as {{{(e^x)^2}}} and let {{{z=e^x}}}. Now replace each {{{e^x}}} with 'z' to get {{{z^2-7z+10=0}}}. From here, solve for 'z' and use the equation {{{z=e^x}}} to find the solutions in terms of 'x'.