Question 220507
{{{(-4-8i)*(3+i)}}} Start with the given expression.



{{{(-4)(3)+(-4)(i)+(-8i)(3)+(-8i)(i)}}} FOIL.



{{{-12-4i-24i-8i^2}}} Multiply.



{{{-12-4i-24i-8(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{-12-4i-24i+8}}} Multiply.



{{{-4-28i}}} Combine like terms.



So {{{(-4-8i)*(3+i)=-4-28i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=-4}}} and {{{b=-28}}}