Question 220503
There are TWO restrictions here.  First of all, the denominator must NEVER equal zero, so x cannot equal 3 or -3.  


Secondly, because of the {{{sqrt(x)}}}, x must be greater than or equal to zero!


Now, take the intersection of these two requirements, and you have all values greater than or equal to zero, except x=3.  In interval notation, this would be

[0,3)U (3, inf)


R^2


Dr. Robert J. Rapalje