Question 29809
{{{ (x^2-x)^2 - 14(x^2-x) + 24 = 0 }}}
first, distribute the power on the first quantity by multiplying the exponents.
{{{ (x^4-x^2) - 14(x^2-x) + 24 = 0 }}} the distribute the 14 to the quantity dont forget to watch your signs
{{{ (x^4-x^2) - 14x^2+14x + 24 = 0 }}} combine like terms
{{{ (x^4) + highlight (-1x^2 - 14x^2) + 14x + 24 = 0 }}}
{{{ x^4 - 15x^2 + 14x + 24 = 0 }}} with 4 terms, you have to factor two of them at a time to find a common factor

{{{ highlight (x^4 - 15x^2) + highlight (14x + 24) = 0 }}}
{{{ x^2(x^2 - 15) + 2(7x + 12) = 0 }}}  I can not get it to factor from here.  Check your signs in the original problem.  Are they correct?