Question 220180
OK, we'll deal in pennies.
Let x=number of nickels; value of the nickels =5x
Then 35-x=number of quarters; value of the quarters=25(35-x)
And we are told that the above values add up to 495, so our equation to solve is:
5x+25(35-x)=495 divide each term by 5----just to reduce the size of the numbers
x+5(35-x)=99  get rid of parens
x+175-5x=99  subtract 175 from each side
x+175-175-5x=99-175  collect like terms
-4x=-76  divide each side by -4
x=19-----------number of nickels
35-x=35-19=16 number of quarters
CK
19*5+16*25=495
95+400=495
495=495

Hope this helps---ptaylor