Question 220211
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The possibilities, given the 2 to 1 probability of an even number result are:


1, 2, 2, 3, 4, 4, 5, 6, 6.


So there are 9 possibilities, only one of which is 5, so *[tex \Large \frac{1}{9}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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