Question 28982
(2x^2 - x - 3)   (3x^2 - 11x - 20)
___________  . _______________
(3x^2+7x + 4)        (4x^2 - 9)


=(2x-3)(x+1)      (x-5)(3x+4)
___________  . _______________
(3x+4)(x+1)      (2x+3)(2x-3)

=(x-5)/(2x+3)   (canceling (2x-3)(x+1)(3x+4) )

Answer: (x-5)/(2x+3)   
Note:(2x^2 - x - 3)   
=2x^2-3x+2x-3
=x(2x-3)+1(2x-3)
=(2x-3)(x+1)

(3x^2 - 11x - 20)
=3x^2-15x+4x-20
=3x(x-5)+4(x-5)
=(x-5)(3x+4)

(3x^2+7x + 4)
=3x^2+4x+3x+4
=x(3x+4)+1(3x+4)
=(3x+4)(x+1)

(4x^2 - 9)
=(2x)^2-(3)^2
= (2x+3)(2x-3)  (using a^2-b^2 = (a+b)(a-b)