Question 220112
First let's reduce the fraction. This almost always makes a problem with fractions easier. Since 15 divides evenly into 300 and 45 we reduce the numerator and denominator by a factor of 15:
{{{300/45 = 20/3}}}
Now we can convert this improper fraction into a mixed number. Divide 20 by 3:
<pre>
    6
   __
3 /20
   18
   --
    2
</pre>
20 divided by 3 is 6 with a remainder of 2. So {{{20/3 = 6&2/3}}}. (Note where the quotient and the remainder go in the mixed number.)