Question 219890
There are probably lots of ways to
do this.
One way is
{{{(A +B)*C + D = 29}}} where
{{{A = 6}}}
{{{B = 8}}}
{{{C = 2}}}
{{{D = 1}}}
Substituting these values:
{{{(6 + 8)*2 + 1 = 29}}}
This is the same as
{{{14*2 + 1 = 29}}}
{{{28 + 1 = 29}}}
{{{29 = 29}}} 
OK