Question 29779
log(x+3) + log(x-7) =2

log[(x+3)(x-7)] = 2
(x+3)(x-7) = 3^2
{{{x^2 - 4x - 21 = 9}}}
{{{x^2 - 4x - 30 = 0}}}


This does not factorise, so use the quadratic formula. The answers are:


{{{ 2 +- sqrt(34) }}}


jon.