<PRE><B>Question 219583</B>
X^2 + 12X 
i am suppose to determin the constant that should be added to the binomial so that it becomes a perfect square trinomial.
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If the coefficient a of the x^2 term = 1, then add
(b/2)^2.
b = 12
(b/2)^2 = 36
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x^2 + 12x + 36 = (x+6)^2
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