Question 219547
To convert from polar to rectangular use the equations (using "t" instead of theta because Algebra.com's formula software doesn't draw theta):
{{{x = r*cos(t)}}} and {{{y = r*sin(t)}}}
Since you r is 2 and {{{cos(300) = 1/2}}} and {{{sin(300) = -sqrt(3)/2}}} we get:
{{{x = 2(1/2) = 1}}} and {{{y = 2(-sqrt(3)/2) = -sqrt(3)}}}
So {{{2(cos(300) + i*sin(300))}}} in rectangular form is ({{{1}}}, {{{-sqrt(3)i}}}).