Question 219522
First we need to understand that
{{{x^(a/b) = root(b, x^a) = (root(b, x))^a}}}<br>
So {{{x^(2/3)(y^5z)^(1/3) = root(3, x^2)*root(3, (y^5z)^1) = root(3, x^2)*root(3, y^5z)}}}
Now, since {{{root(n, a)*root(n, b) = root(n, a*b)}}}, we can combine these into a single radical:
{{{root(3, x^2)*root(3, y^5z) = root(3, x^2y^5z)}}}