Question 219500
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Let *[tex \Large x] represent the first of three consecutive odd integers.  The next consecutive odd integer must then be *[tex \Large x + 2] and the one after that must be *[tex \Large (x + 2) + 2 = x + 4].


Eight times the first integer is then *[tex \Large 8x].


"Is" means "=".


Twice the second consecutive odd integer is *[tex \Large 2(x + 2)].


Putting it all together:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 8x\ =\ 2(x + 2)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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