Question 219469
Let x = the smaller number and y = the larger number.
{{{x+y = 23}}} Rewrite this as {{{x = 23-y}}} and substitute for x in the equation below:
{{{2y+3x = 57}}
{{{2y+3(23-y) = 57}}} Solve for y.
{{{2y+69-3y = 57}}}
{{{-y+69 = 57}}} Subtract 69 from both sides.
{{{-y = -12}}} Multiply both sides by -1.
{{{highlight(y = 12)}}} and {{{x = 23-12}}} so...
{{{highlight(x = 11)}}}