Question 219415
The general point-slope form is:
{{{y - y[1] = m(x - x[1])}}}
where m is the slope and ({{{x[1]}}}, {{{y[1]}}}) is a point on the line.<br>
In your equation:
{{{y= (10/7)(x-11)}}}
we can see that the m is 10/7 and that {{{x[1]}}} is 11. But what is the {{{y[1]}}}? Your equation has just "y" on the left side. It's "supposed" to be {{{y - y[1]}}}. What would {{{y[1]}}} have to be in order for {{{y - y[1]}}} to be just "y"? In other words, y minus what number is equal to y? I hope by now that it is obvious that {{{y[1] = 0}}}.<br>
So the slope is 10/7 and the point on the graph is (11, 0).