Question 219149
Let P(E)=0.25 and P(F)=0.45
1. Find P(E and F) if P(E or F)=0.6
P(E and F) = P(E)+P(F)-P(E or F)
P(E and F) = 0.25+0.45-0.6 = 0.1
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2. Find P(E and F) if E and F are mutually exclusive.
P(E and F) = 0
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3. Find P(Fc)
P(F') = 1-0.45 = 0.55
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Cheers,
Stan H.