Question 219202
The consecutive numbers are 
{{{n}}}
{{{n+1}}}
given:
{{{(n + n+1)/3 = 71}}}
{{{(2n + 1)/3 = 71}}}
{{{2n + 1 = 213}}}
{{{2n = 212}}}
{{{n = 106}}}
{{{n + 1 = 107}}}
The numbers are 106 and 107
check:
{{{(n + n+1)/3 = 71}}}
{{{(106 + 107)/3 = 71}}}
{{{213/3 = 71}}}
{{{213 = 213}}}
OK