Question 219158


{{{7(a+1)+3=(1/7)(49a+70)}}} Start with the given equation.



{{{7a+7+3=7a+10}}} Distribute.



{{{7a+10=7a+10}}} Combine like terms on the left side.



{{{7a=7a+10-10}}} Subtract {{{10}}} from both sides.



{{{7a-7a=10-10}}} Subtract {{{7a}}} from both sides.



{{{0a=10-10}}} Combine like terms on the left side.



{{{0a=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>always</b></font> true for any a value, this means a can equal any number. 



So there are an infinite number of solutions.