Question 219079


{{{2x-6y=18}}} Start with the given equation.



{{{-6y=18-2x}}} Subtract {{{2x}}} from both sides.



{{{-6y=-2x+18}}} Rearrange the terms.



{{{y=(-2x+18)/(-6)}}} Divide both sides by {{{-6}}} to isolate y.



{{{y=((-2)/(-6))x+(18)/(-6)}}} Break up the fraction.



{{{y=(1/3)x-3}}} Reduce.



So the equation {{{y=(1/3)x-3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=1/3}}} and the y-intercept is {{{b=-3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-3\right)]