Question 218863
OK.

Let x=amount of 68% juice that is needed

Now we know that the amount of pure sugar in the 20% juice (0.20*1) plus the amount of pure sugar in the 68% juice that is added(0.68x) has to equal the amount of pure sugar in the final mixture (0.24(1+x)), so our equation to solve is:

0.20*1+0.68x=0.24(1+x)  get rid of parens
0.20*1+0.68x=0.24+0.24x or
0.20+0.68x=0.24+0.24x  subtract 0.24x and also 0.20 from each side of the equation
0.20-0.20+0.68x-0.24x=0.24-0.20 combine like terms

0.44x=0.04  divide each side by 0.44
x=0.091 gal-------------amount of 68% juice that is needed


CK
0.20*1 +0.091*0.68=(1.091)*0.24
0.20+0.062=0.262
0.262=0.262


Hope this helps---ptaylor