Question 218773
{{{8-2(x-3)<4(x-10)+8}}}


Step 1.  Multiply to get rid of parenthesis


{{{8-2x+6<4x-40+8}}}


{{{14-x<4x-32}}}


Step 2.  Add x+32 to both sides of inequality


{{{14-x+x+32<4x-32+x+32}}}


{{{52<4x}}}


Step 3.  Divide 4 to both sides of the inequality


{{{52/4<4x/4}}}


{{{13<x}}}


Step 4.  ANSWER {{{13<x}}}



I hope the above steps were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J

http://www.FreedomUniversity.TV