Question 218689
Line 1 is described by the equation 3y - 2x = -3. Line 2 goes through the origin and intersects line 1 at x=6. What equation describes line 2?


Step 1. At x=6 then to find y substitute into 3y-2x=-3


{{{3y-2*6=-3}}}


Add 12 to both sides of the equation


{{{3y-12+12=-3+12}}}


{{{3y=9}}}


Divide 3 to both sides of the equation


{{{3y/3=9/3}}}


{{{y=3}}}


Step 2.  The intersection point is (6,3)


Step 3.  We can find the equation of line 2 with these two points:  (0,0) and (6,3).


Step 4.  Slope {{{m=(3-0)/(6-0)=1/2}}} and y-intercept b=0 since it passes through the origin (0,0)


Step 5.  ANSWER: The equation is {{{y=x/2}}}


I hope the above steps and explanation were helpful. 


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Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.


Respectfully, 
Dr J


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